| Author |
Math: Order to Chaos |
Kanman
Grand Admiral
Pitch Black
Joined: August 26, 2005
Posts: 1017
From: Virginia, United States
|  Posted: 2008-04-05 17:10
So, I was messing around with more particles. This time, rather than coding them with instructions on how to move based on the other particles, I decided to let math functions (sin, cos, etc) move them around. Also, instead of the usual x,y,z coordinates, I decided to use spherical (roe,phi,theta).
Well, what did I get, but a bunch of spheres (surprise, surprise). Then I wanted to manipulate it. I wanted to bend it and fold it. I added control variables literally randomly, with no idea what would occur or if it would do anything at all.
Now, I behold some really interesting things. See for yourself.
Controls:
Modes: keys 1-4 above the letter keys. There are four different 'modes'. Since they are really just random set ups of the controls, I cannot define that with any names or behavior.
Mode 1 is no interactive. it was the prototype. Mode 2-4 do stuff.
Keys: (not all keys do something in all modes and most you have to hold down to see their influence). The keys are in pairs, each pair assigned to a variable. One key increasing the variable while the other decreases the variable.
Pairs: Q&W, S&D, X&C, V&B. Each pair is written in order of Decreaser&Increaser.
Other Keys: R = reset, T freezes/unfreezes Time.
LMouse and Rmouse rotate camera view.
Spherical Math
[ This Message was edited by: Kanman *FC* on 2008-04-05 17:27 ]
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YIIMM
Grand Admiral
Joined: June 16, 2005
Posts: 851
From: Barcino, Hispania Tarraconensis
| Posted: 2008-04-05 18:37
It does look very pretty, I mean I'm not entirely sure what all the commands do without seeing the equations behind them, but the effects are...well, pretty.
(By the way, are spherical coordinates the same as polar coordinates?)
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codenemesis
Admiral
Joined: June 10, 2007
Posts: 185
| Posted: 2008-04-05 20:51
I guess i really dont understand what all this is, i wouldnt mind trying to learn though, could you point me to where i might find out?
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Kanman
Grand Admiral
Pitch Black
Joined: August 26, 2005
Posts: 1017
From: Virginia, United States
| Posted: 2008-04-05 21:13
The equations behind the shapes are practically garbage. It is like those days in math class, when you are bored and playing with your graphing calculator. You put things into it just to see what happens, like y = x * cos(ln(x))^e^x.
The equations a like that. If you want to really see what is happening, ill put them here. It will be messy and hard to read, but ill do it.
To understand polar coordinates, see it this way: R is the hypoteneuse of X and Y. Roe is the hypoteneuse of R and Z. So, there is Roe (its the distance from the origin along a straight line). Theta is the angle laying around the XY plane. Phi is the angle with respect to the Z axis. I know that sounds complicated. see wikipedia for visuals and better explanations.
Mostly, I am just trying to make familiar shapes. So far I have made a dolphin fin, a wine glass, a light bulb, various vortices and singularities, and even achieved what appears to be pure formless chaos. I also think I have come up with a bell, a sea shell, and a tuba, a cone with blades sticking out and teeth.
mode equations:
mode 1:
if(ROE[i]>0.9*(A/10000.0) && PHI[i] > 0.05)
PHI[i] -= 0.01;
if(PHI[i] < 0.05 && ROE[i] > 0.001)
ROE[i] -= 0.01;
if(ROE[i] < 0.001 && PHI[i] < 0.05)
PHI[i] += 3.1415-2*PHI[i];
if(PHI[i] > 0.05 && ROE[i] < 0.9*(A/10000.0))
ROE[i] += 0.01;
THETA[i] += 0.025;
if(THETA[i] > 2*3.1415)
THETA[i] -= 2*3.1415;
mode 2:
ROE[i] = pow(sin(PHI[i]),B)*pow(cos(THETA[i]),C)/1.5+0.1*D;
PHI[i] += 0.015;
if(PHI[i] > 3.1415)
PHI[i] -= 3.1415;
THETA[i] += 0.025;
if(THETA[i] > 2*3.1415)
THETA[i] -= 2*3.1415;
mode 3:
PHI[i] = pow(sin((ROE[i]/(0.9*A/(10000.0*W))*3.1415)),B)*pow(cos(THETA[i]),C)/1.5+0.1*D;
ROE[i] += 0.001;
if(ROE[i] > 0.9*(A/10000.0))
ROE[i] -= 0.9*(A/10000.0)-0.001;
THETA[i] += 0.001;
if(THETA[i] > 2*3.1415)
THETA[i] -= 2*3.1415;
mode 4:
PHI[i] = pow(tan((ROE[i]/(0.9*A/10000.0)*3.1415*W)),B)*pow(cos(THETA[i]),C)/1.5+0.1*D;
ROE[i] -= 0.015;
if(ROE[i] < 0.001)
ROE[i] += 0.9*(A/10000.0);
THETA[i] += 0.025;
if(THETA[i] > 2*3.1415)
THETA[i] -= 2*3.1415;
mode 5: *I dont remember if you have mode 5*
PHI[i] = pow(cos((ROE[i]/(0.9*A/10000.0)*3.1415*W)),B)*pow(tan(THETA[i]),C)/1.5+0.1*D;
ROE[i] -= 0.015;
if(ROE[i] < 0.001)
ROE[i] += 0.9*(A/10000.0);
THETA[i] += 0.025;
if(THETA[i] > 2*3.1415)
THETA[i] -= 2*3.1415;
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|Kakashi|
Fleet Admiral
Joined: April 04, 2007
Posts: 448
| Posted: 2008-04-05 22:18
Is this like Mathletics.... Or something?
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Sonlox ~hes that sexy~
Admiral
Sundered Weimeriners
Joined: November 19, 2003
Posts: 76
From: Bedford, Nova Scotia
| Posted: 2008-04-05 23:12
POST COUNT +1
HAHAHAHHAA
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